Question

rationalise the denomination (a) 1/2√5 b) 1/√7-√5​

Answer 1

Step-by-step explanation:

by multiplying it's conjugate u get urs answer perfectly

Answer 2

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Question :

Rationalise the denominator :

$\rm{(a) \dfrac{1}{2 \sqrt{5}}}$

$\rm{(b) \: \dfrac{1}{\sqrt{7} -\sqrt{5}}}$

Answer:

$\star \sf \frac{1}{2 \sqrt{5} }$

$\implies \sf \: \frac{1}{2 \sqrt{5} } \times \frac{ \sqrt{5} }{ \sqrt{5} }$

$\implies \sf \: \frac{ \sqrt{5} }{2 \times 5}$

$\implies \boxed{ \bf{ \pink{ \frac{ \sqrt{5} }{10} } \: is \: the \: answer}}$

$\star \sf \: \frac{1}{ \sqrt{7} - \sqrt{5} }$

$\implies \sf \: \frac{1}{ \sqrt{7} - \sqrt{5} } \times \frac{ \sqrt{7} + \sqrt{5} }{ \sqrt{7} + \sqrt{5} }$

$\implies \sf \: \frac{ \sqrt{7} + \sqrt{5} }{7 - 5}$

$\implies \sf \: \frac{ \sqrt{7} + \sqrt{5} }{2}$

$\implies \boxed{ \pink{ \bf{ \frac{ \sqrt{7} + \sqrt{5} }{2} }} \sf \: is \: the \: answer}$