Question

Rationalise the denomination of 1/√7-√3​

Answer 1

Answer & Solution is in this picture!!!

I hope it will help you!!!

Answer 2

Solution:

Given to rationalise,

$\tt = \dfrac{1}{ \sqrt{7} - \sqrt{3} }$

Multiplying both numerator and denominator by √7 + √3, we get,

$\tt = \dfrac{1 \times ( \sqrt{7} + \sqrt{3} ) }{( \sqrt{7} - \sqrt{3} )( \sqrt{7} + \sqrt{3}) }$

Using identity (a + b)(a - b) = a² - b², we get,

$\tt = \dfrac{\sqrt{7} + \sqrt{3}}{( \sqrt{7} )^{2} - ( \sqrt{3})^{2} }$

$\tt = \dfrac{\sqrt{7} + \sqrt{3}}{7 - 3}$

$\tt = \dfrac{\sqrt{7} + \sqrt{3}}{4}$

Which is our required answer.

Answer:

• After rationalization, we get - (√7 + √3)/4

Steps to rationalise:

• Multiply both numerator and denominator by the rationalising factor of denominator.
• Simply and get the result.