Question

rationalise the denomination of 2√3-3√2/3√2+2√3

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Answer 1

Answer:

2root6-5

Step-by-step explanation:

(2root3-3root2)/(3root2+2root3) multiply it by (3root2-2root3)/(3root2-2root3)

we get,

(6root6-12-18+6root6)/(18-12)

(12root6-30)/6

2root6-5 is the rationalized form