Question

rationalise the denomination
question =14/3-√2

Answer 1

heya...

Here is your answer...
$14 \div 3 - \sqrt{2}$
$rationalizing \: factor \: of \: 3 - \sqrt{2} is \: 3 + \sqrt{2}$
$14 \div 3 - \sqrt{2} \times 3 + \sqrt{2} \div 3 + \sqrt{2}$

$42 + \sqrt{2} \div {3}^{2} - \sqrt{2} ^{2}$
$42 + \sqrt{2} \div 9 - 2$

$42 + \sqrt{2} \div 7$

It may help you...☺☺