Question

rationalise the denominator

1)1/√2
2)1/√7​

Answer 1

$\huge\star\underline\mathtt\purple{Answer:-}$

1)= $\frac{1}{ \sqrt{2} }$

= $\frac{1}{ \sqrt{2} } \times \frac{ \sqrt{2} }{ \sqrt{2} }$

= $\frac{ \sqrt{2} }{ { \sqrt{(2)} }^{2} }$

= $\frac{ \sqrt{2} }{2}$

_____________________

2) = $\frac{1}{ \sqrt{7} }$

= $\frac{1}{ \sqrt{7} } \times \frac{ \sqrt{7} }{ \sqrt{7} }$

= $\frac{ \sqrt{7} }{ { \sqrt{(7)} }^{2} }$

= $\frac{ \sqrt{7} }{7}$

Answer 2

★Answer:-

rationalising the denominator

$\huge \bf \implies \: \frac{1}{ \sqrt{2} } \times \frac{ \sqrt{2} }{ \sqrt{2} } = \frac{ \sqrt{2} }{2} \\ \\ \huge \bf \implies \: \frac{1}{ \sqrt{7} } \times \frac{ \sqrt{7} }{ \sqrt{7} } = \frac{ \sqrt{7} }{7}$