Question

rationalise the denominator 1) 1 by / 2√7 +3√3

Answer 1

Heya !

$\frac{1}{2 \sqrt{7} + 3 \sqrt{3} }$

On rationalizing the denominator we get,

$= \frac{1}{ 2\sqrt{7} + 3 \sqrt{3} } \times \frac{2 \sqrt{7} - 3 \sqrt{3} }{2 \sqrt{7} - 3 \sqrt{3} } \\ \\ = \frac{2 \sqrt{7} - 3 \sqrt{3} }{ {(2 \sqrt{7} )}^{2} - {(3 \sqrt{3} )}^{2} } \\ \\ = \frac{2 \sqrt{7} - 3 \sqrt{3} }{28 - 27} \\ \\ = 2 \sqrt{7} - 3 \sqrt{3}$

Hope this helps ☺

Answer 2

Answer:

Step-by-step explanation: