Question

rationalise the denominator 1/√2+√3
plz give the answer in picture form​

Answer 1

$\sf\frac{1}{ \sqrt{2} + \sqrt{3} } = \frac{1}{ \sqrt{3} + \sqrt{2} } \times \frac{ \sqrt{3} - \sqrt{2} }{ \sqrt{3} - \sqrt{2} }$

$\sf \frac{1}{ \sqrt{2} + \sqrt{3} } = \frac{ \sqrt{3} - \sqrt{2} }{( \sqrt{3} ) ^{2} - ( \sqrt{2} ) {}^{2} }$

$\sf \frac{1}{ \sqrt{2} + \sqrt{3} } = \frac{ \sqrt{3} - \sqrt{2} }{3 - 2}$

$\boxed{ \sf \frac{1}{ \sqrt{2} + \sqrt{3} } = \sqrt{3} - \sqrt{2} }$

Answer 2

Answer:

Step-by-step explanation:

1/√2 + √3 * √2 - √3/√2 - √3

= √2 - √3 / √4 - √9

= √2 - √3 / 2 - 3

= √2 - √3 /  -1

= - ( √2 - √3 )

= -√2 + √3

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