Math, asked by ayushlanjekar13, 10 months ago

rationalise the denominator
1/√3-√2-1

Answers

Answered by pritujha1405
3

Answer:

Step-by-step explanation:

we have

1/√3-√2-1

=>1(√3+√2+1)/√3-√2-1(√3+√2+1)

=>√3+√2+1/(√3+√2)^2-1

=> √3+√2+1/3+2+2√6-1

=>√3+√2+1/2√6+4

=>√3+√2+1(2√6-4)/2√6+4(2√6-4)

=>2√2+2√6-4/8

=>√2+√6-2/4

Hope it helps.....

Please mark it as the brainliest

Answered by Anonymous
0

hii dear here is the answer...mark as brainlist

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