Question

Rationalise the denominator.
1/√3-√2+1
solve that........​

Answer 1

Answer:

$\frac{1}{ \sqrt{} {3} - \sqrt{2} + 1} \\ = \frac{1}{ \sqrt{3} - \sqrt{2} + 1 } \times \frac{ \sqrt{3} + \sqrt{2} + 1}{ \sqrt{3} + \sqrt{2} + 1 } \\ = \frac{ \sqrt{3} + \sqrt{2} + 1}{ {( \sqrt{3)} }^{2} - ( \sqrt{2} + 1) {}^{2} } \\ = \frac{ \sqrt{3} + \sqrt{2} + 1}{3 - 2 + 1} \\ = \sqrt{3} + \sqrt{2} + 1$

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Answer 2

Step-by-step explanation:

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