Question

rationalise the denominator 1/√3-√2​

Answer 1

Answer:

Lets see -

Step-by-step explanation:

1/root3 - root2 x root3 + root2 / root3 + root2

= root3 + root2/ root3^2 - root2^2

= root3 + root2 / 3 - 2

= root3 + root2 / 1

= root3 + root2

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Answer 2

$\frac{1}{ \sqrt{3} - \sqrt{2} } \\ Multiplying \: numerator \: and \: denominator \: with \: the \: conjugate \: \: \sqrt{3} + \sqrt{2} \\ \\ \frac{(1)( \sqrt{3 } + \sqrt{2})}{ (\sqrt{3} - \sqrt{2})( \sqrt{3} + \sqrt{2} )} \\ = \frac{\sqrt{3} + \sqrt{2}}{3 - 2} \\ = \sqrt{3} + \sqrt{2}$

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