rationalise the denominator 1/√3+√2+√5
Answers
Answered by
0
heya dear
u answer about example below
13√+4√−7√=13√−7√+2=1(3√−7√)+2×(3√−7√)−2(3√−7√)−2=(3√−7√)+2(3√−7√)2−22=3√−7√+23+7−221√−4=3√−7√+26−221√=3√−7√+26−221√×6+221√6+221√=63√+67√−67√−143√+12+421√36−84=421√+12−83√−48=21√+3−23√−12=23√−21√−312
hope u understand
I hope this help u
u answer about example below
13√+4√−7√=13√−7√+2=1(3√−7√)+2×(3√−7√)−2(3√−7√)−2=(3√−7√)+2(3√−7√)2−22=3√−7√+23+7−221√−4=3√−7√+26−221√=3√−7√+26−221√×6+221√6+221√=63√+67√−67√−143√+12+421√36−84=421√+12−83√−48=21√+3−23√−12=23√−21√−312
hope u understand
I hope this help u
Similar questions