Question

rationalise the denominator 1) 3/3+6√2​

Answer 1

Answer:

$\frac{3}{3 + 6\sqrt{2} } \times \frac{3 - \sqrt[6]{2} }{3 - \sqrt[6]{2} } \\ \frac{ 3(3 - \sqrt[6]{2})}{9 - 12} \\ = - (3 - \sqrt[6]{2} ) \\ \sqrt[6]{2} - 3$

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