rationalise the denominator 1/√3 +√4-√7
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=1/√3+√4-√7
=1+√12-√21/√3
=(1+√12-√21)√3/√3×√3
=√3+√36-√63/3
=√3+6-3√7/3
=1+√12-√21/√3
=(1+√12-√21)√3/√3×√3
=√3+√36-√63/3
=√3+6-3√7/3
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