Question

rationalise the denominator 1/3+√5​

Answer 1

AnsweR :-

$\dfrac{1}{ 3 + \sqrt{5} }$

$\dfrac{1}{3 + \sqrt{5}} \times \dfrac{3 - \sqrt{5} }{3 - \sqrt{5} }$

$\dfrac{3 - \sqrt{5}}{{(3)}^{2} - {( \sqrt{5})}^{2}}$

$\dfrac{3 - \sqrt{5} }{9 - 5}$

$\dfrac{3 - \sqrt{5}}{4}$

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Procedure :-

$\implies$ First of all we will see the expression after that we will multiply the denominator with the numerator and denominator both.

$\implies$ Then we cannot multiply a simple number with a under root number so we will write it in 3√5 way in numerator and will square the 3 and √5.

$\implies$ After squaring it the numerator will not change but we will supract the denominator as (a+b)(a-b) identity is used.

$\implies$ The denominator will remain the same but the denominator will become 4, hence the answer will be 3√5/4

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Answer 2

Answer:

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