Math, asked by khatrideepu20, 10 months ago

Rationalise the denominator 1/(√3+√7+√5)​

Answers

Answered by nagarishithakalluri
2

Answer:

1/√3+√7+√5

=1/√3+√7+√5(√3+√7-√5/√3+√7-√5)

=√3+√7-√5/5+2√21

=(√3+√7-√5)(5-2√21)/-59

Answered by pushkar92
3

Answer:

BRO I'LL GIVE U THE FORMULA' SO U CAN DO IT BY UR SELF OKAY.

 =  \frac{1}{( \sqrt{3} +  \sqrt{7} +  \sqrt{5}  }  \\ =  \frac{1 \times ( \sqrt{3} -  \sqrt{7} -  \sqrt{5}) }{ (\sqrt{3} +  \sqrt{7} +  \sqrt{5} ) \times ( \sqrt{3} -  \sqrt{7} +  \sqrt{5} ) }

AFTER THIS PLZ DO IT YOURSELF.

PLZ MARK ME AS BRAINLIEST

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