Rationalise the denominator 1/(√3+√7+√5)
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Answer:
1/√3+√7+√5
=1/√3+√7+√5(√3+√7-√5/√3+√7-√5)
=√3+√7-√5/5+2√21
=(√3+√7-√5)(5-2√21)/-59
Answered by
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Answer:
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