rationalise the denominator 1/√5-√3
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Answered by
9
hey mate here's your ans.
1/√5-√3=1/√5-√3x√3+√5/√5+√3
=√5+√3/(√5)^2-(√3)^2
=√5+√3/5-3=√5+√3/2
....
1/√5-√3=1/√5-√3x√3+√5/√5+√3
=√5+√3/(√5)^2-(√3)^2
=√5+√3/5-3=√5+√3/2
....
Answered by
5
1/√5-√3= 1*√5+√3/(√5-√3)(√5-√3)
= √5+√3/(√5)^2-(√3)^2
= √5+√3/5-3
= √5+√3/2
= √5+√3/(√5)^2-(√3)^2
= √5+√3/5-3
= √5+√3/2
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