Math, asked by jasmin14, 1 year ago

rationalise the denominator 1/√5-√3

Answers

Answered by prashant279
9
hey mate here's your ans.
1/√5-√3=1/√5-√3x√3+√5/√5+√3
=√5+√3/(√5)^2-(√3)^2
=√5+√3/5-3=√5+√3/2
....
Answered by varsha145
5
1/√5-√3= 1*√5+√3/(√5-√3)(√5-√3)
= √5+√3/(√5)^2-(√3)^2
= √5+√3/5-3
= √5+√3/2
Similar questions