Question

Rationalise the denominator 1/√6+√5-√11

Answer 1

Step-by-step explanation:

your answer is (6√5+5√6+√330)/60

refer to attachment

Answer 2

$\frac{1}{ (\sqrt{6} + \sqrt{5} )- \sqrt{11} } \times \frac{( \sqrt{6} + \sqrt{5}) + \sqrt{11} }{( \sqrt{6} + \sqrt{5}) + \sqrt{11} } \\ \\ = \frac{ \sqrt{6} + \sqrt{5} + \sqrt{11} }{ {( \sqrt{6} + \sqrt{5} ) }^{2} - {( \sqrt{11)} }^{2} } \\ \\ = \frac{ \sqrt{6} + \sqrt{5} + \sqrt{11} }{6 + 5 + 2 \sqrt{30} - 11} \\ \\ = \frac{ \sqrt{6} + \sqrt{5} + \sqrt{11} }{2 \sqrt{30} } \\ \\ = \frac{ \sqrt{30 \: (} \sqrt{6} + \sqrt{5} + \sqrt{11} )}{60} \\ \\ = \frac{6 \sqrt{5} + 5 \sqrt{6} + \sqrt{330} }{60}$