Question

rationalise the denominator:1/√6-√5+√3​

Answer 1

Answer:

See the attachment and follow the procedure

Answer 2

Answer:

(√6-√5+8√3+2√90)÷(-56)

Step-by-step explanation:

[1×(√6-√5)+√3]÷(√6-√5)+√3×[√6-√5+√3]

(√6-√5+√3)÷(√6-√5)² - (√3)²

[√6-√5+√3)÷[(√6)² - 2√30 + (√5)²]-3

(√6-√5+√3)÷8-2√30

[√6-√5+√3(8+2√30)]÷(8-2√30)×(8+2√30)

(√6-√5+8√3+2√90)÷64-120 [ by the formula a²-b²=(a+b)(a-b)]

(√6-√5+8√3+2√90)÷(-56)