Question

rationalise the denominator 1÷7-2√3​

Answer 1

1/7+3√2

=1/7+3√2× 7-3√2/7-3√2

=7-3√2/ (7+3√2)(7-3√2)

=7-3√2/(7)^2-(3√2)^2

=7-3√2/49-18

=7-3√2/31

Hope it helps! :)

Answer 2

1/7-2✓3

=1/7-2✓3*7+2✓3/7+2✓3

=7+2✓3/(7)²-(2✓3)² (using (a+b)(a-b) = a²- b²)

=7+2✓3/49-4*3

=7+2✓3/49-12

=7+2✓3/37

this is ur answer

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