rationalise the denominator 1÷7-2√3
Answers
Answered by
8
1/7+3√2
=1/7+3√2× 7-3√2/7-3√2
=7-3√2/ (7+3√2)(7-3√2)
=7-3√2/(7)^2-(3√2)^2
=7-3√2/49-18
=7-3√2/31
Hope it helps! :)
=1/7+3√2× 7-3√2/7-3√2
=7-3√2/ (7+3√2)(7-3√2)
=7-3√2/(7)^2-(3√2)^2
=7-3√2/49-18
=7-3√2/31
Hope it helps! :)
Answered by
2
1/7-2✓3
=1/7-2✓3*7+2✓3/7+2✓3
=7+2✓3/(7)²-(2✓3)² (using (a+b)(a-b) = a²- b²)
=7+2✓3/49-4*3
=7+2✓3/49-12
=7+2✓3/37
this is ur answer
plz mark it as brainliest
Similar questions