Question

Rationalise the denominator

1
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7+3root 2

Answer 1

Hari Om....!

To rationalise denominator, we generally multiply numerator and denominator by its conjugate.
$\frac{1}{7 + 3 \sqrt{2} } = \frac{1}{7 + 3 \sqrt{2} } \times \frac{7 - 3 \sqrt{2} }{7 - 3 \sqrt{2 } } \\ = > \frac{7 - 3 \sqrt{2} }{ {7}^{2} - {(3 \sqrt{2}) }^{2} } \\ = > \frac{7 - 3 \sqrt{2} }{49 - 18} \\ = > \frac{7 - 3 \sqrt{2} }{31} answer$


Regards

KSHITIJ

Answer 2

HEY MATE HERE IS YOUR ANSWER

Que :- Rationalisation

$\frac{1}{7 + 3 \sqrt{2} }$

Ans :-

$= > \frac{1}{7 + 3 \sqrt{2} } \times \frac{7 - 3 \sqrt{2} }{7 - 3 \sqrt{2} }$

By using identity

➡️ a^2 + b^2

We get,



$\huge = > \frac{7 - 3 \sqrt{2} }{ {7}^{2} - (3 \sqrt{2 {)}^{2} } }$






$\huge = > \frac{7 - 3 \sqrt{2} }{49 - 18}$







$\huge = > \frac{7 - 3 \sqrt{2} }{31}$
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