Question

Rationalise the denominator 1/ (√7+√6 )​

Answer 1

Answer:

your answer dear..............

Answer 2

$\frac{1}{ \sqrt{7} + \sqrt{6} } \\ = \frac{1}{ \sqrt{7} + \sqrt{6} } \times \frac{ \sqrt{7} - \sqrt{6} }{ \sqrt{7} - \sqrt{6} } \\ = \frac{ \sqrt{7} - \sqrt{6} }{ {( \sqrt{7}) }^{2} - { (\sqrt{6}) }^{2} } \\ = \frac{ \sqrt{7} - \sqrt{6} }{7 - 6} \\ = \frac{ \sqrt{7} - \sqrt{6} }{1} \\ = \sqrt{7} - \sqrt{6}$

Hence, your answer is √7-√6