Math, asked by anushkashah001, 9 months ago

rationalise the denominator : 1 by root 6 - root 5​

Answers

Answered by Anonymous
31

Answer:

 =  \frac{1}{ \sqrt{6} -   \sqrt{5} }  \\  \\  =  \frac{1 \times ( \sqrt{6}   +  \sqrt{5} )}{( \sqrt{6}  -  \sqrt{5} )( \sqrt{6}  +  \sqrt{5} )}   \\  \\  =  \frac{ \sqrt{6}  + \sqrt{5}  }{( \sqrt{6}) {}^{2}  -  (\sqrt{5} ) {}^{2}  }  \\  \\   = \frac{ \sqrt{6}  +  \sqrt{5} }{6 - 5}  \\  \\  =   \frac{ \sqrt{6}  +  \sqrt{5}  }{1}  \\  \\  =  \sqrt{6} +  \sqrt{5}

Step-by-step explanation:

Hope it helps you....... ❤

please mark it as brainliest.........

Answered by pantradhakrishan
13

It is the answer i hope this helps you this is most easy question in the worldpls mark as brainliest

Attachments:
Similar questions