Question

rationalise the denominator 1/ root 13​

Answer 1

To rationalise it we should multioly with the same number given on denominator with both numerator & denomintor

$\frac{1}{ \sqrt{13} } \\ \\ = \geqslant \frac{1}{ \sqrt{13} } \times \frac{ \sqrt{13} }{ \sqrt{13} } \\ \\ = \geqslant \frac{ \sqrt{13} }{( \sqrt{13) {}^{2} } } \\ \\ = \geqslant (\sqrt{13} {}^{2} ) = 13 \\ \\ = \geqslant so \: \frac{ \sqrt{13} }{13}$

Answer 2

Answer:

To rationalise it we should multioly with the same number given on denominator with both numerator & denomintor

\begin{gathered} \frac{1}{ \sqrt{13} } \\ \\ = \geqslant \frac{1}{ \sqrt{13} } \times \frac{ \sqrt{13} }{ \sqrt{13} } \\ \\ = \geqslant \frac{ \sqrt{13} }{( \sqrt{13) {}^{2} } } \\ \\ = \geqslant (\sqrt{13} {}^{2} ) = 13 \\ \\ = \geqslant so \: \frac{ \sqrt{13} }{13} \end{gathered}

13

1

=⩾

13

1

×

13

13

=⩾

(

13)

2

13

=⩾(

13

2

)=13

=⩾so

13

13