Question

rationalise the denominator 1/root 7+root 3-root2​

Answer 1

1/√7+√3-√2=

=1(√7+√3+√2)/10+2√21-2=

=√7+√3+√2/8+2√21

=(√7+√3+√2)(8-2√21)/64-84

=(√7+√3+√2)(8-2√22)/-20

Answer 2

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