Question

rationalise the denominator 1/root5+root6-root2

Answer 1

I hope this answer helps uh

Answer 2

Solution:-

given by:-

$\frac{1}{ \sqrt{5} } + \sqrt{6} - \sqrt{2} \\ \frac{1 + \sqrt{30} - \sqrt{10} }{ \sqrt{5} } \\ \frac{1 + \sqrt{30} - \sqrt{10} }{ \sqrt{5} } \times \frac{ \sqrt{5} }{ \sqrt{5} } \\ \frac{ \sqrt{5} + \sqrt{150} - \sqrt{50} }{5} \\ \frac{ \sqrt{5} + 5 \sqrt{6 } - 5 \sqrt{2} }{5}$