Question

rationalise the denominator 1 upon 2-√3​

Answer 1

Step-by-step explanation:

$\frac{1}{2 - \sqrt{3} } \times \frac{2 + \sqrt{3} }{2 + \sqrt{3} } = \frac{2 + \sqrt{3} }{4 - 37} = \frac{2 + \sqrt{3} }{1}$

Answer 2

Answer:

$\huge\frak\red{Answer}$

$\frac{1}{2 + \sqrt{3} }$

$= \frac{1}{2 + \sqrt{3} } \times \frac{2 - \sqrt{3} }{2 - \sqrt{3} }$

$= \frac{2 - \sqrt{3} }{2² - ( \sqrt{3)²} }$

$= \frac{2 - \sqrt{3} }{4 - 3}$

$= \frac{2 - \sqrt{3} }{1}$

$= 2 - \sqrt{3}$