Question

Rationalise the denominator 1
upon 7+3√2​

Answer 1

Answer:

(7-3√2)/31

Step-by-step explanation:

1/(7+3√2)

=1×(7-3√2)/(7+3√2)(7-3√2)

=(7-3√2)/7²-(3√2)²

=(7-3√2)/49-(9×2)

=(7-3√2)/49-18

=(7-3√2)/31

hope that it helps you

Answer 2

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Question:-

$⇢ \frac{1}{7 + 3 \sqrt{2} }$

⇢ Rationalise it

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Solution:-

$⇢ \frac{1}{7 + 3 \sqrt{2} } \times \frac{7 - 3 \sqrt{2} }{7 - 3 \sqrt{2} } \\ \\ ⇢ \frac{7 - 3 \sqrt{2} }{ {(7)}^{2} - {(3 \sqrt{2} )}^{2} } \\ \\ ⇢ \frac{7 - 3 \sqrt{2} }{49 - 18} \\ \\ ⇢ \frac{7 - 3 \sqrt{2} }{31}$

Hence, Rationalised...

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How we have solve this

⇢ First see what is given in denominator.

⇢ Change the sign of number given denominator and multiple it to whole fraction.

⇢ Solve it further ..you will get your answer.

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Hope this helps you

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