Question

Rationalise the denominator: 1 upon root 2+root 3+root 5

Answer 1

= 1 / (√2 + √3 + √5)
= 1 / (√2 + √3 ) + (√5 ) * ( √2 + √3 ) -  ( √5 )/( √2 + √3 ) - ( √5 )
= √2 + √3 - √5  / (√2 + √3 ) + ( √5 ) * (√2 +√3 ) - ( √5 )
= √2 + √3 - √5 / ( √2 + √3 )^2 - (√5 )^2
= √2 + √3 - √5 / (2 + 3 + 2√6 - 5 )
= √2 + √3 -√5 / 5 - 5 + 2√6
= √2 + √3 - √5 / 2√6
= √2 + √3 - √5 / 2√6 * √6 / √6
= √6 (√2 + √3 - √5 ) / 2√6 *√6
= √12 + √18 - √30 / 2 * 6
= √12 + √18 - √30 / 12
i hope that this will help u........................^_^

Answer 2

Answer:

i hope useful to you, that solve