Math, asked by suryanshtuktuk, 9 months ago

rationalise the denominator 1 upon underroot 7-underroot 3

Answers

Answered by MkTinu

2

Answer:

1/(√7-√3) ×(√7+√3) /(√7+√3 )
√7+√3 /√7²-√3²
√7+√3 / 7-3
√7+√3 / 4

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