Math, asked by sakuni6927, 6 months ago

rationalise the denominator 10÷2√2-√3​

Answers

Answered by Anonymous
2

Answer:

here is your answer

hope it helps ☺️...........

Attachments:
Answered by Anonymous
1

Answer:

4 \sqrt{2}  + 2 \sqrt{3}

Step-by-step explanation:

 \frac{10}{2 \sqrt{2}  -  \sqrt{3} }  =  \frac{10(2 \sqrt{2} +  \sqrt{3} ) }{(2 \sqrt{2} -  \sqrt{3} )(2 \sqrt{2} +  \sqrt{3} )  }

 \frac{10(2 \sqrt{2} +  \sqrt{3})}{(2 \sqrt{2})^{2} - ( \sqrt{3})^{2}}  =  \frac{10(2 \sqrt{2} +  \sqrt{3}) }{8 - 3}

 \frac{10(2 \sqrt{2} +  \sqrt{3})  }{5} = 2(2 \sqrt{2}   +  \sqrt{3} )

 = 4 \sqrt{2}  + 2 \sqrt{3}

So the answer is 4√2 + 2√3

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