Question

rationalise the denominator 10 upon 2 root 2 minus root 3​

Answer 1

CORRECT QUESTION :-

★ Rationalise the denominator : 10/2√2 - √3.

GIVEN :-

• 10/2√2 - √3.

TO RATIONALIZE

• The denominator of 10/2√2 - √3.

SOLUTION

→ 10/2√2 - √3

★ By rationalizing the denominator ★

→ {(10)(2√2 + √3)}/{(2√2 - 3)(2√2 + 3)}

★ By using identity :- (a + b)(a - b) = a² - b².

→ (20√2 + 10√3)/{(2√2)² - (3)²}

→ (20√2 + 10√3)/(4√4 - 9)

→ (20√2 + 10√3)/(4√2² - 9)

→ (20√2 + 10√3)/(4 × 2- 9)

→ (20√2 + 10√3)/(8 - 9)

→ (20√2 + 10√3)/(-1)

★ Transpose the negative (- ve) sign to the numerator ★

→ -(20√2 + 10√3)/1

Hence the Rationalise form of The denominator of 10/2√2 - √3 is [-(20√2 + 10√3)/1].