Question

Rationalise the denominator- 14/ 5√3 -√5​

Answer 1

$\frac{ - 14}{5 \sqrt{3} - \sqrt{5} } \\ = \frac{ - 70 \sqrt{3} - 14 \sqrt{5} }{75 - 5} \\ = \frac{14(5 \sqrt{3} - \sqrt{5} )}{70} \\ = \frac{ {5 \sqrt{3} - \sqrt{5} } }{5}$

HOPE THIS COULD HELP!!!

Answer 2

$\frac{-14}{5\sqrt3-\sqrt5}=-25\sqrt3+5\sqrt5$

Step-by-step explanation:

Given : Expression $\frac{-14}{5\sqrt3-\sqrt5}$

To find : Rationalize the denominator ?

Solution :

To rationalize the denominator multiply and divide expression by $5\sqrt3+\sqrt5$

$=\frac{-14}{5\sqrt3-\sqrt5}\times \frac{5\sqrt3+\sqrt5}{5\sqrt3+\sqrt5}$

$=\frac{-14(5\sqrt3+\sqrt5)}{(5\sqrt3)^2-(\sqrt5)^2}$

$=\frac{-14(5\sqrt3+\sqrt5)}{75-5}$

$=\frac{-14(5\sqrt3+\sqrt5)}{70}$

$=-5(5\sqrt3+\sqrt5)$

$=-25\sqrt3+5\sqrt5$

#Learn more

Rationalised​ the denominator of  3/√2

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