Question

Rationalise the denominator

Answer 1

Answer:

Your answer is :

$17 - 12 \sqrt{2}$

Step-by-step explanation:

Let's take common first

$\frac{2(3 - 2 \sqrt{2} )}{2(3 + 2 \sqrt{2}) }$

2 will be cancel

Let's rationalize the Denominator

$\frac{3 - 2 \sqrt{2} }{3 + 2 \sqrt{2} } \times \frac{3 - 2 \sqrt{2} }{3 - 2 \sqrt{2} }$

by using,

$(a + b)(a - b) = a {}^{2} - b {}^{2}$

$\frac{(3 - 2 \sqrt{2 } ) \times (3 - 2 \sqrt{2} ) }{9 - 4 \times 2}$

$\frac{(3 - 2 \sqrt{2}) \times (3 - 2 \sqrt{2}) }{9 - 8}$

$\frac{(3 -2 \sqrt{2} ) \times (3 - 2 \sqrt{2}) }{1}$

$17 - 12 \sqrt{2}$

Hope you understand.