Question

Rationalise the denominator​

Answer 1

Answer:

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Answer 2

Question :-

$\frac{3 + \sqrt{2} }{4 \sqrt{2} }$

What to do =rationalisation?

Solution :-

We know that :

The rationalisation factor is =

$\sqrt{32}$

Hence,

$\frac{3 + \sqrt{2} }{4 \sqrt{2} } \\ \\ (\frac{3 + \sqrt{2} }{ \sqrt{32} } \times )( \frac{ \sqrt{32} }{ \sqrt{32} } ) \\ \\ \frac{3 \sqrt{32} + \sqrt{2} \times \sqrt{32} }{ \sqrt{32} \times \sqrt{3 2} } \\ \\ \frac{3 \times 4 \sqrt{2} + \sqrt{2} \times 4 \sqrt{2} }{32} \\ \\ \frac{12 \sqrt{2} + 8}{32} \\ \\ \frac{4(3 \sqrt{2} + 2)}{32} \\ \\ \frac{3 \sqrt{2} + 2}{8} = \frac{6.24}{8} = 0.78 \: \: \: \: \: ans$