Question

rationalise the denominator 2/√3-√2​

Answer 1

Answer:

2(rt3 + rt2)

Step-by-step explanation:

Multiply the denominator and the numerator by rt3 + rt2

= 2/(rt3 - rt2) x (rt3 + rt2)/(rt3 + rt2)

= 2(rt 3 + rt2)/(3-2)

= 2(rt3 + rt2)

Answer 2

Answer:

Step-by-step explanation:

2/√3-√2 × √3+√2÷√3+√2

2(√3+√2)÷(√3-√2)(√3+√2)

We know that (a-b)(a+b) = a²-b²

(√3-√2)(√3+√2) = √3² - √2²

Both square and root are cancelled

2(√3+√2) ÷ 3-2

2√3+2√2 ÷ 1

hence, the answer is 2√3 + 2√2.

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