Question

Rationalise the denominator 2+3√3 /1+2√7

Answer 1

Answer:

(2+3√3 )/(1+2√7) × (1-2√7) /(1- 2√7)

(2+3√3 )(1-2√7) / (1+2√7) (1-2√7)

2(1-2√7) +3√3(1-2√7) / 1^2 - (2√7)^2

2 -2√7 + 3√3 - 6√21/ 1 - (4*7)

2 -2√7 + 3√3 - 6√21 / 1 - 28

2 -2√7 + 3√3 - 6√21 / (-27)

2(1-√7) + 3(√3 - 2√21)/(-27)