Math, asked by payalmehta758, 10 months ago

rationalise the denominator 2√3-√5/2√2+3√3​

Answers

Answered by fatima106hadian
0

Answer: 4√6-18-2√10+3√15/-19

Step-by-step explanation:

2√3-√5/2√2+3√3× 2√2-3√3/2√2-3√3

=4√6-6×3-2√10+3√15/4×2-9×3

= 4√6-18-2√10+3√15/-19

Answered by aradhanagoswami35122
0

Answer:

Hii

hope it's correct.

I tried my best to do this.

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