rationalise the denominator 2/3✓7...
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Answer:
3
3
+
2
3
5
−
7
Rationalizing the denominator by multiplying and dividing denominator by opposite sign,
=\frac{3\sqrt{5}-\sqrt{7}}{3\sqrt{3}+\sqrt{2}}\times\frac{3\sqrt{3}-\sqrt{2}}{3\sqrt{3}-\sqrt{2}}=
3
3
+
2
3
5
−
7
×
3
3
−
2
3
3
−
2
=\frac{(3\sqrt{5}-\sqrt{7})(3\sqrt{3}-\sqrt{2})}{(3\sqrt{3})^2-(\sqrt{2})^2}=
(3
3
)
2
−(
2
)
2
(3
5
−
7
)(3
3
−
2
)
=\frac{9\sqrt{15}-3\sqrt{10}-3\sqrt{21}+\sqrt{14}}{27-2}=
27−2
9
15
−3
10
−3
21
+
14
=\frac{9\sqrt{15}-3\sqrt{10}-3\sqrt{21}+\sqrt{14}}{25}=
25
9
15
−3
10
−3
21
+
14
I hope it helps you
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