rationalise the denominator 2÷√5-√3
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=>. 2 / √5 - √√3
RATIONALISING THE DENOMINATOR OF. 2 / √5 - √√3 ;
NOW , MULTIPLYING THE NUMERATOR AND DENOMINATOR OF IRRATIONAL BY √5 + √3 ,WE GET ;
=>. 2 / √5 - √√3 × √5 + √3/ √ 5 + √3
=>. 2( √5 + √3) / (√5 × √5 ) + ( √3 × √3)
=>. 2 √ 5 + 2√ 3 / (√5) ^2 + (√3) ^ 2
=>. 2√5 + 2√3. /. 5. + 3
=>. 2√5 +. 2√3 / 8
SO THE RATIONALISED DENOMINATOR OF 2 / √5 - √√3 IS 2√5 +. 2√3 / 8 .
THANKS FRIEND, HOPE IT HELPS
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