Math, asked by tkfidha90, 8 days ago

rationalise the denominator 2/√5+√8√13

Answers

Answered by ItzKajalKaLover
2

Answer:

 \frac{2}{ \sqrt{5} +  \sqrt{8}  \sqrt{13}  }  \\  =  \frac{2}{ \sqrt{5 }  +  \sqrt{104} } \times  \frac{ \sqrt{5}  -   \sqrt{104}  }{ \sqrt{5}   -  \sqrt{104} }   \\  =  \frac{2( \sqrt{5} -  \sqrt{104} ) }{( \sqrt{5} )^{2}  - ( \sqrt{104} ) ^{2} }  \\  =  \frac{2( \sqrt{5}  -  \sqrt{104}  )\: }{5 - 104}  \\  =  \frac{2( \sqrt{5}  -  \sqrt{104} )}{ - 99}

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