Question

Rationalise the denominator 2/7+3√2​

Answer 1

$= \frac{2}{7 + 3 \sqrt{2} } \times \frac{7 - 3 \sqrt{2} }{7 - 3 \sqrt{2} } \\ = \frac{14 - 6 \sqrt{2} }{(7) {}^{2} - (3 \sqrt{2}) {}^{2} } \\ = \frac{14 - 6 \sqrt{2} }{49 - 18} \\ = \frac{14 - 6 \sqrt{2} }{31} \\ = \frac{14}{31} - \frac{6}{31} \sqrt{2}$

Answer 2

Answer:

$\frac{2}{7 + 3 \sqrt{2} } = \frac{2}{7 + 3 \sqrt{2} } \times \frac{7 - 3 \sqrt{2} }{7 - 3 \sqrt{2} } = \frac{14 - 6 \sqrt{2} }{49 - 18} = \frac{14 - 6 \sqrt{2} }{31}$

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