Math, asked by abhay74krishna, 9 months ago

Rationalise the denominator 2/√7-√5​

Answers

Answered by ishwarsinghdhaliwal
3

Answer:

  \sqrt{7}  +  \sqrt{5}

Step-by-step explanation:

 \frac{2}{ \sqrt{7} -  \sqrt{5}  }  \times  \frac{ \sqrt{7} +  \sqrt{5}  }{ \sqrt{7} +  \sqrt{5}  }  \\  =  \frac{2 \sqrt{7}  + 2 \sqrt{5} }{( \sqrt{7} )^{2}  - ( \sqrt{5})^{2}  }  \\= \frac{2 \sqrt{7}  + 2 \sqrt{5} }{7  - 5}\\=  \frac{2( \sqrt{7}  +  \sqrt{5} )}{2}  \\  =  \sqrt{7}  +  \sqrt{5}

Similar questions