Math, asked by Kamaan6008, 7 months ago

Rationalise the denominator 2 by 3 + root 5

Answers

Answered by ishwarsinghdhaliwal
0

 =  \frac{2}{3 +  \sqrt{5} }  \times  \frac{3 -  \sqrt{5} }{3 -  \sqrt{5} } \\ =   \frac{6 - 2 \sqrt{5} }{3 ^{2}  -  (\sqrt{5} )^{2} }  </p><p>\\ =  \frac{6 - 2 \sqrt{5} }{9 - 5}   \\ =    \frac{6 - 2 \sqrt{5} }{4}  \\ =   \frac{3 -  \sqrt{2} }{2}

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