Question

rationalise the denominator​

Answer 1

Step-by-step explanation:

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Answer 2

$\frac{1}{ \sqrt[2]{3} + 3 }$

$\frac{1}{ \sqrt[2]{3} + 3 } \times \frac{ \sqrt[2]{3} - 3 }{ \sqrt[2]{3} - 3 }$

$= \frac{ \sqrt[2]{3} - 3 }{( {\sqrt[2]{3}})^{2} - ( {3})^{2} }$

$= \frac{ \sqrt[2]{3} - 3 }{12 - 9}$

$= \frac{ \sqrt[2]{3} + 3}{3}$

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