Math, asked by Nikitatiwari, 1 year ago

rationalise the denominator 2underoot3 -underoot5/2underoot 2 +3 underoot 3

Answers

Answered by ATHARVT
1
just change the sign and multiply and divide by same term.
Answered by Manikumarsingh
6

 \frac{2 \sqrt{3}  -  \sqrt{5}  }{2 \sqrt{2} + 3 \sqrt{3}  }   \times  \frac{2 \sqrt{2}  - 3 \sqrt{3} } { 2 \sqrt{2}  - 3 \sqrt{3} }
 \frac{4 \sqrt{6} - 18 - 2 \sqrt{10 } + 3 \sqrt{15}   }{8 - 27}
 \frac{4 \sqrt{6} - 18 - 2 \sqrt{10 } + 3 \sqrt{15}   }{ - 19}


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