Math, asked by manikamahi5, 10 days ago

rationalise the denominator √3+√5/√3-√5​

Answers

Answered by SANDHIVA1974
1

Step-by-step explanation:

</p><p>\begin{gathered} \frac{3 + \sqrt{5} }{3 - \sqrt{5} } \\ \\ rationalise - - &gt; \\ \\ = &gt; \frac{3 + \sqrt{5} }{3 - \sqrt{5} } \times \frac{3 + \sqrt{5} }{3 + \sqrt{5} } \\ \\ = &gt; \frac{ ({3 + \sqrt{5}) }^{2} }{ {(3)}^{2} - ( { \sqrt{5} )}^{2} } \\ \\ = &gt; \frac{9 + 5 + 2(3)( \sqrt{5} )}{9 - 5} \\ \\ = &gt; \frac{14 + 6 \sqrt{5} }{4} \\ \\ = &gt; \frac{2(7 + 3 \sqrt{5} )}{4} \\ \\ = &gt; \frac{7 + 3 \sqrt{5} }{2} \end{gathered}</p><p>Cathenna • Ace

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