Question

rationalise the denominator √3+√5/√3-√5​

Answer 1

Step-by-step explanation:

$</p><p>\begin{gathered} \frac{3 + \sqrt{5} }{3 - \sqrt{5} } \\ \\ rationalise - - > \\ \\ = > \frac{3 + \sqrt{5} }{3 - \sqrt{5} } \times \frac{3 + \sqrt{5} }{3 + \sqrt{5} } \\ \\ = > \frac{ ({3 + \sqrt{5}) }^{2} }{ {(3)}^{2} - ( { \sqrt{5} )}^{2} } \\ \\ = > \frac{9 + 5 + 2(3)( \sqrt{5} )}{9 - 5} \\ \\ = > \frac{14 + 6 \sqrt{5} }{4} \\ \\ = > \frac{2(7 + 3 \sqrt{5} )}{4} \\ \\ = > \frac{7 + 3 \sqrt{5} }{2} \end{gathered}</p><p>Cathenna • Ace$