Question

rationalise the denominator 3/√7-2

Answer 1

3/√7-2
=3/√7-2×√7+2/√7+2
=3√7+6/(√7)^2-(2)^2
=3√7+6/7-4
=3√7+6/3heres your answer I hope you'll understand what I had done
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Answer 2

Answer:

Step-by-step explanation:

Definition of square root:

In mathematics, the square root is a factor that, when multiplied by itself, equals the original integer. For instance, the square roots of 9 are both 3 and -3.

Definition of rational number:

In mathematics, any number that can be written as p/q where q 0 is considered a rational number. Additionally, every fraction that has an integer denominator and numerator and a denominator that is not zero falls into the category of rational numbers. The outcome of dividing a rational number, or fraction, will be a decimal number, either a terminating decimal or a repeating decimal.

Given:

$3/\sqrt7-2$

Find:

rationalise the denominator  $3/\sqrt7-2$

Solution:

$3/\sqrt7-2$

Multiply  $\sqrt7 + 2$  with numerator and denominator of $3/\sqrt 7 - 2$

$(3/\sqrt7 - 2 )* (\sqrt7 + 2/\sqrt7 +2)$

$3 \sqrt 7 +6 / (7 - 4)$

$3\sqrt 7 +6 / 3$

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