Question

Rationalise the denominator

3/√7-√2
please help me and reply answer with full explanation

class 9 maths ncert​

Answer 1

$\frac{3}{ \sqrt{7} - \sqrt{2 } } \\ by \: rationalise \: the \: denominator \\ \frac{3}{ \sqrt{7} - \sqrt{2} } × \ \frac{ \sqrt{7} + \sqrt{2} }{ \sqrt{7 } + \sqrt{2 } } \\ \frac{3( \sqrt{7} + \sqrt{2)} }{( \sqrt{7} - \sqrt{2})( \sqrt{7 } - \sqrt{2)} } \\ \frac{3( \sqrt{7} + \sqrt{2)} }{7 - 2} \\ using \: identity \: x {}^{2} - y {}^{2} = (x - y)(x + y) \\ \frac{3 (\sqrt{7} + \sqrt{2)} }{5} \\ hence \: rationalised$

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