Question

Rationalise the denominator 3 by √6-√7
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Answer 1

Answer:

$\frac{3}{ \sqrt{6} - \sqrt{7} } \times \frac{ \sqrt{6} + \sqrt{7} }{ \sqrt{6} + \sqrt{7} } \\ = \frac{3( \sqrt{6} + \sqrt{7} )}{( \sqrt{6 } {)}^{2} - ( \sqrt{7} {)}^{2} } \\ = \frac{ 3 \sqrt{6} + 3 \sqrt{7} }{6 - 7} \\ = \frac{3 \sqrt{6} + 3 \sqrt{7} }{ - 1} \\ = - (3 \sqrt{6} + 3 \sqrt{7} ) \\ = - 3 \sqrt{6} - 3 \sqrt{7}$

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