Question

rationalise the denominator 3 root 2 / root 6 -root 3​

Answer 1

Answer:

√6+√12=√6(1+√2)

Step-by-step explanation:

conjugate of √6-√3=√6+√3

multiply and divide(√6+√3)

...

=3√2(√6+√3)÷{(√6-√3)(√6+√3)}

{(a+b)(a-b)=a^2-b^2}

=3√2(√6+√3)÷[6-3]

=√2(√6+√3)

=√12+√6